Base | Representation |
---|---|
bin | 10100100001010111001… |
… | …101000101001100000001 |
3 | 11222211000010021101212222 |
4 | 110201113031011030001 |
5 | 141101103323220001 |
6 | 2555502000100425 |
7 | 203612242640522 |
oct | 24412715051401 |
9 | 4884003241788 |
10 | 1410212320001 |
11 | 4a40820aa481 |
12 | 1a9385304715 |
13 | a2ca05a3184 |
14 | 4c37ca3a849 |
15 | 26a399ac61b |
hex | 14857345301 |
1410212320001 has 2 divisors, whose sum is σ = 1410212320002. Its totient is φ = 1410212320000.
The previous prime is 1410212319979. The next prime is 1410212320003. The reversal of 1410212320001 is 1000232120141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1285196332225 + 125015987776 = 1133665^2 + 353576^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1410212320001 is a prime.
Together with 1410212320003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1410212320003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705106160000 + 705106160001.
It is an arithmetic number, because the mean of its divisors is an integer number (705106160001).
Almost surely, 21410212320001 is an apocalyptic number.
It is an amenable number.
1410212320001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410212320001 is an equidigital number, since it uses as much as digits as its factorization.
1410212320001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1410212320001 its reverse (1000232120141), we get a palindrome (2410444440142).
The spelling of 1410212320001 in words is "one trillion, four hundred ten billion, two hundred twelve million, three hundred twenty thousand, one".
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