Base | Representation |
---|---|
bin | 1100110100111010001101… |
… | …1110100100001001011000 |
3 | 1211221020121201000112221002 |
4 | 3031032203132210021120 |
5 | 3322031142301100402 |
6 | 45554514541404132 |
7 | 2653626316613033 |
oct | 315164336441130 |
9 | 54836551015832 |
10 | 14103120331352 |
11 | 4548110839928 |
12 | 16b9342569648 |
13 | 7b3bc30598b0 |
14 | 36a847a9a01a |
15 | 196cc404a602 |
hex | cd3a37a4258 |
14103120331352 has 32 divisors (see below), whose sum is σ = 28485973750080. Its totient is φ = 6507185207040.
The previous prime is 14103120331253. The next prime is 14103120331369. The reversal of 14103120331352 is 25313302130141.
It is a super-3 number, since 3×141031203313523 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19934549 + ... + 20629892.
It is an arithmetic number, because the mean of its divisors is an integer number (890186679690).
Almost surely, 214103120331352 is an apocalyptic number.
It is an amenable number.
14103120331352 is an abundant number, since it is smaller than the sum of its proper divisors (14382853418728).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14103120331352 is a wasteful number, since it uses less digits than its factorization.
14103120331352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40567803 (or 40567799 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 14103120331352 its reverse (25313302130141), we get a palindrome (39416422461493).
The spelling of 14103120331352 in words is "fourteen trillion, one hundred three billion, one hundred twenty million, three hundred thirty-one thousand, three hundred fifty-two".
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