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14103125174797 is a prime number
BaseRepresentation
bin1100110100111010001111…
…0001000010101000001101
31211221020122001010121212221
43031032203301002220031
53322031200021043142
645554515233255341
72653626406024621
oct315164361025015
954836561117787
1014103125174797
11454811354787a
1216b9344104551
137b3bc4064339
1436a84859b181
15196cc46a5767
hexcd3a3c42a0d

14103125174797 has 2 divisors, whose sum is σ = 14103125174798. Its totient is φ = 14103125174796.

The previous prime is 14103125174717. The next prime is 14103125174843. The reversal of 14103125174797 is 79747152130141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13128020274121 + 975104900676 = 3623261^2 + 987474^2 .

It is an emirp because it is prime and its reverse (79747152130141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14103125174797 - 231 = 14100977691149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14103125174717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051562587398 + 7051562587399.

It is an arithmetic number, because the mean of its divisors is an integer number (7051562587399).

Almost surely, 214103125174797 is an apocalyptic number.

It is an amenable number.

14103125174797 is a deficient number, since it is larger than the sum of its proper divisors (1).

14103125174797 is an equidigital number, since it uses as much as digits as its factorization.

14103125174797 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1481760, while the sum is 52.

The spelling of 14103125174797 in words is "fourteen trillion, one hundred three billion, one hundred twenty-five million, one hundred seventy-four thousand, seven hundred ninety-seven".