Base | Representation |
---|---|
bin | 1100110100111011000010… |
… | …0110001100001110000111 |
3 | 1211221021012001011221102112 |
4 | 3031032300212030032013 |
5 | 3322032120122344221 |
6 | 45554552443131235 |
7 | 2653634631505442 |
oct | 315166046141607 |
9 | 54837161157375 |
10 | 14103340434311 |
11 | 45482140024a7 |
12 | 16b93a4213b1b |
13 | 7b3c2983212b |
14 | 36a868dd2659 |
15 | 196cd852615b |
hex | cd3b098c387 |
14103340434311 has 2 divisors, whose sum is σ = 14103340434312. Its totient is φ = 14103340434310.
The previous prime is 14103340434301. The next prime is 14103340434317. The reversal of 14103340434311 is 11343404330141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14103340434311 is a prime.
It is a super-2 number, since 2×141033404343112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14103340434317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051670217155 + 7051670217156.
It is an arithmetic number, because the mean of its divisors is an integer number (7051670217156).
Almost surely, 214103340434311 is an apocalyptic number.
14103340434311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103340434311 is an equidigital number, since it uses as much as digits as its factorization.
14103340434311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 14103340434311 its reverse (11343404330141), we get a palindrome (25446744764452).
The spelling of 14103340434311 in words is "fourteen trillion, one hundred three billion, three hundred forty million, four hundred thirty-four thousand, three hundred eleven".
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