14110312023887 has 2 divisors, whose sum is σ = 14110312023888. Its totient is φ = 14110312023886.

The previous prime is 14110312023839. The next prime is 14110312023889. The reversal of 14110312023887 is 78832021301141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14110312023887 is a prime.

It is a super-2 number, since 2×14110312023887² (a number of 27 digits) contains 22 as substring.

Together with 14110312023889, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110312023889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055156011943 + 7055156011944.

It is an arithmetic number, because the mean of its divisors is an integer number (7055156011944).

Almost surely, 2^{14110312023887} is an apocalyptic number.

14110312023887 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110312023887 is an equidigital number, since it uses as much as digits as its factorization.

14110312023887 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 41.

The spelling of 14110312023887 in words is "fourteen trillion, one hundred ten billion, three hundred twelve million, twenty-three thousand, eight hundred eighty-seven".