141104112123031 has 2 divisors, whose sum is σ = 141104112123032. Its totient is φ = 141104112123030.

The previous prime is 141104112122989. The next prime is 141104112123049. The reversal of 141104112123031 is 130321211401141.

141104112123031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141104112123031 - 2¹³ = 141104112114839 is a prime.

It is a super-2 number, since 2×141104112123031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141104112122987 and 141104112123005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141104112123071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70552056061515 + 70552056061516.

It is an arithmetic number, because the mean of its divisors is an integer number (70552056061516).

Almost surely, 2^{141104112123031} is an apocalyptic number.

141104112123031 is a deficient number, since it is larger than the sum of its proper divisors (1).

141104112123031 is an equidigital number, since it uses as much as digits as its factorization.

141104112123031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 141104112123031 its reverse (130321211401141), we get a palindrome (271425323524172).

The spelling of 141104112123031 in words is "one hundred forty-one trillion, one hundred four billion, one hundred twelve million, one hundred twenty-three thousand, thirty-one".