Base | Representation |
---|---|
bin | 1100110101010111101100… |
… | …1011010010101101000101 |
3 | 1211222000001020012221010011 |
4 | 3031111323023102231011 |
5 | 3322143344214001000 |
6 | 50002304121430221 |
7 | 2654326403011060 |
oct | 315257313225505 |
9 | 54860036187104 |
10 | 14111034125125 |
11 | 4550501987263 |
12 | 16ba99093b371 |
13 | 7b48847787c2 |
14 | 36ad98b238d7 |
15 | 1970d8bb82ba |
hex | cd57b2d2b45 |
14111034125125 has 32 divisors (see below), whose sum is σ = 20820379057920. Its totient is φ = 9342477748800.
The previous prime is 14111034125099. The next prime is 14111034125179. The reversal of 14111034125125 is 52152143011141.
It is not a de Polignac number, because 14111034125125 - 211 = 14111034123077 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 278024559 + ... + 278075308.
It is an arithmetic number, because the mean of its divisors is an integer number (650636845560).
Almost surely, 214111034125125 is an apocalyptic number.
It is an amenable number.
14111034125125 is a deficient number, since it is larger than the sum of its proper divisors (6709344932795).
14111034125125 is an equidigital number, since it uses as much as digits as its factorization.
14111034125125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 556099918 (or 556099908 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 14111034125125 its reverse (52152143011141), we get a palindrome (66263177136266).
The spelling of 14111034125125 in words is "fourteen trillion, one hundred eleven billion, thirty-four million, one hundred twenty-five thousand, one hundred twenty-five".
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