141111100211 has 2 divisors, whose sum is σ = 141111100212. Its totient is φ = 141111100210.

The previous prime is 141111100189. The next prime is 141111100213. The reversal of 141111100211 is 112001111141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141111100211 - 2¹⁰ = 141111099187 is a prime.

Together with 141111100213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141111100213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70555550105 + 70555550106.

It is an arithmetic number, because the mean of its divisors is an integer number (70555550106).

Almost surely, 2^141111100211 is an apocalyptic number.

141111100211 is a deficient number, since it is larger than the sum of its proper divisors (1).

141111100211 is an equidigital number, since it uses as much as digits as its factorization.

141111100211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 141111100211 its reverse (112001111141), we get a palindrome (253112211352).

The spelling of 141111100211 in words is "one hundred forty-one billion, one hundred eleven million, one hundred thousand, two hundred eleven".