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14111143254311 is a prime number
BaseRepresentation
bin1100110101011000000110…
…1011100101100100100111
31211222000022211120021012212
43031112001223211210213
53322144110133114221
650002323020434035
72654332166415005
oct315260153454447
954860284507185
1014111143254311
114550558543674
1216baa013a891b
137b48a126769c
1436ada940da75
151970e3572b5b
hexcd581ae5927

14111143254311 has 2 divisors, whose sum is σ = 14111143254312. Its totient is φ = 14111143254310.

The previous prime is 14111143254259. The next prime is 14111143254319. The reversal of 14111143254311 is 11345234111141.

14111143254311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14111143254311 - 214 = 14111143237927 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14111143254319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055571627155 + 7055571627156.

It is an arithmetic number, because the mean of its divisors is an integer number (7055571627156).

Almost surely, 214111143254311 is an apocalyptic number.

14111143254311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111143254311 is an equidigital number, since it uses as much as digits as its factorization.

14111143254311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5760, while the sum is 32.

Adding to 14111143254311 its reverse (11345234111141), we get a palindrome (25456377365452).

The spelling of 14111143254311 in words is "fourteen trillion, one hundred eleven billion, one hundred forty-three million, two hundred fifty-four thousand, three hundred eleven".