14111230412141 has 2 divisors, whose sum is σ = 14111230412142. Its totient is φ = 14111230412140.

The previous prime is 14111230412137. The next prime is 14111230412143. The reversal of 14111230412141 is 14121403211141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9150298302916 + 4960932109225 = 3024946^2 + 2227315^2 .

It is an emirp because it is prime and its reverse (14121403211141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14111230412141 - 2² = 14111230412137 is a prime.

Together with 14111230412143, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14111230412141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14111230412143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055615206070 + 7055615206071.

It is an arithmetic number, because the mean of its divisors is an integer number (7055615206071).

Almost surely, 2^{14111230412141} is an apocalyptic number.

It is an amenable number.

14111230412141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111230412141 is an equidigital number, since it uses as much as digits as its factorization.

14111230412141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 14111230412141 its reverse (14121403211141), we get a palindrome (28232633623282).

The spelling of 14111230412141 in words is "fourteen trillion, one hundred eleven billion, two hundred thirty million, four hundred twelve thousand, one hundred forty-one".