Base | Representation |
---|---|
bin | 10100100010001101100… |
… | …011101010110111000110 |
3 | 11222220100200011021100221 |
4 | 110202031203222313012 |
5 | 141104440244224032 |
6 | 3000132253054554 |
7 | 203643654613342 |
oct | 24421543526706 |
9 | 4886320137327 |
10 | 1411124211142 |
11 | 4a44aa913818 |
12 | 1a959a78745a |
13 | a30b74a1129 |
14 | 4c427bb0622 |
15 | 26a8ea87597 |
hex | 1488d8eadc6 |
1411124211142 has 8 divisors (see below), whose sum is σ = 2161722195936. Its totient is φ = 690550145832.
The previous prime is 1411124211109. The next prime is 1411124211157. The reversal of 1411124211142 is 2411124211141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×14111242111422 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7505979753 + ... + 7505979940.
It is an arithmetic number, because the mean of its divisors is an integer number (270215274492).
Almost surely, 21411124211142 is an apocalyptic number.
1411124211142 is a deficient number, since it is larger than the sum of its proper divisors (750597984794).
1411124211142 is a wasteful number, since it uses less digits than its factorization.
1411124211142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15011959742.
The product of its digits is 512, while the sum is 25.
Adding to 1411124211142 its reverse (2411124211141), we get a palindrome (3822248422283).
Subtracting 1411124211142 from its reverse (2411124211141), we obtain a palindrome (999999999999).
The spelling of 1411124211142 in words is "one trillion, four hundred eleven billion, one hundred twenty-four million, two hundred eleven thousand, one hundred forty-two".
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