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1411124211142 = 24715011959693
BaseRepresentation
bin10100100010001101100…
…011101010110111000110
311222220100200011021100221
4110202031203222313012
5141104440244224032
63000132253054554
7203643654613342
oct24421543526706
94886320137327
101411124211142
114a44aa913818
121a959a78745a
13a30b74a1129
144c427bb0622
1526a8ea87597
hex1488d8eadc6

1411124211142 has 8 divisors (see below), whose sum is σ = 2161722195936. Its totient is φ = 690550145832.

The previous prime is 1411124211109. The next prime is 1411124211157. The reversal of 1411124211142 is 2411124211141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14111242111422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7505979753 + ... + 7505979940.

It is an arithmetic number, because the mean of its divisors is an integer number (270215274492).

Almost surely, 21411124211142 is an apocalyptic number.

1411124211142 is a deficient number, since it is larger than the sum of its proper divisors (750597984794).

1411124211142 is a wasteful number, since it uses less digits than its factorization.

1411124211142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15011959742.

The product of its digits is 512, while the sum is 25.

Adding to 1411124211142 its reverse (2411124211141), we get a palindrome (3822248422283).

Subtracting 1411124211142 from its reverse (2411124211141), we obtain a palindrome (999999999999).

The spelling of 1411124211142 in words is "one trillion, four hundred eleven billion, one hundred twenty-four million, two hundred eleven thousand, one hundred forty-two".

Divisors: 1 2 47 94 15011959693 30023919386 705562105571 1411124211142