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1411124314111 is a prime number
BaseRepresentation
bin10100100010001101100…
…100000011111111111111
311222220100200100111121121
4110202031210003333333
5141104440311022421
63000132255211411
7203643655522501
oct24421544037777
94886320314547
101411124314111
114a44aa984116
121a959a816b67
13a30b7508c65
144c427bd9d71
1526a8eaa7d41
hex1488d903fff

1411124314111 has 2 divisors, whose sum is σ = 1411124314112. Its totient is φ = 1411124314110.

The previous prime is 1411124314027. The next prime is 1411124314133. The reversal of 1411124314111 is 1114134211141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1411124314111 - 27 = 1411124313983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411124314811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705562157055 + 705562157056.

It is an arithmetic number, because the mean of its divisors is an integer number (705562157056).

Almost surely, 21411124314111 is an apocalyptic number.

1411124314111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411124314111 is an equidigital number, since it uses as much as digits as its factorization.

1411124314111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 25.

Adding to 1411124314111 its reverse (1114134211141), we get a palindrome (2525258525252).

The spelling of 1411124314111 in words is "one trillion, four hundred eleven billion, one hundred twenty-four million, three hundred fourteen thousand, one hundred eleven".