1411124983 has 2 divisors, whose sum is σ = 1411124984. Its totient is φ = 1411124982.

The previous prime is 1411124977. The next prime is 1411125047. The reversal of 1411124983 is 3894211141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1411124983 - 2⁵ = 1411124951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411127983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705562491 + 705562492.

It is an arithmetic number, because the mean of its divisors is an integer number (705562492).

Almost surely, 2^1411124983 is an apocalyptic number.

1411124983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411124983 is an equidigital number, since it uses as much as digits as its factorization.

1411124983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 34.

The square root of 1411124983 is about 37564.9435378253. The cubic root of 1411124983 is about 1121.6443170329.

The spelling of 1411124983 in words is "one billion, four hundred eleven million, one hundred twenty-four thousand, nine hundred eighty-three".