Base | Representation |
---|---|
bin | 10100100010001110101… |
… | …111001010001110100111 |
3 | 11222220102001101200011021 |
4 | 110202032233022032213 |
5 | 141110010331003143 |
6 | 3000134241152011 |
7 | 203644315044133 |
oct | 24421657121647 |
9 | 4886361350137 |
10 | 1411144000423 |
11 | 4a450aaaa7a3 |
12 | 1a95a532b607 |
13 | a30bb60c671 |
14 | 4c42a6823c3 |
15 | 26a91695ced |
hex | 1488ebca3a7 |
1411144000423 has 2 divisors, whose sum is σ = 1411144000424. Its totient is φ = 1411144000422.
The previous prime is 1411144000403. The next prime is 1411144000439. The reversal of 1411144000423 is 3240004411141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1411144000423 - 229 = 1410607129511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1411144000403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705572000211 + 705572000212.
It is an arithmetic number, because the mean of its divisors is an integer number (705572000212).
Almost surely, 21411144000423 is an apocalyptic number.
1411144000423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411144000423 is an equidigital number, since it uses as much as digits as its factorization.
1411144000423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1411144000423 its reverse (3240004411141), we get a palindrome (4651148411564).
The spelling of 1411144000423 in words is "one trillion, four hundred eleven billion, one hundred forty-four million, four hundred twenty-three", and thus it is an aban number.
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