Base | Representation |
---|---|
bin | 10100100010001111000… |
… | …111001100101111111101 |
3 | 11222220102111020211120121 |
4 | 110202033013030233331 |
5 | 141110013434132310 |
6 | 3000135024214541 |
7 | 203644422441520 |
oct | 24421707145775 |
9 | 4886374224517 |
10 | 1411150302205 |
11 | 4a4513614386 |
12 | 1a95a746a451 |
13 | a30bca07b27 |
14 | 4c42b442bb7 |
15 | 26a91edd0da |
hex | 1488f1ccbfd |
1411150302205 has 16 divisors (see below), whose sum is σ = 1976468267520. Its totient is φ = 947057709312.
The previous prime is 1411150302143. The next prime is 1411150302217. The reversal of 1411150302205 is 5022030511141.
It is a cyclic number.
It is not a de Polignac number, because 1411150302205 - 27 = 1411150302077 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1411150302205.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 428919420 + ... + 428922709.
It is an arithmetic number, because the mean of its divisors is an integer number (123529266720).
Almost surely, 21411150302205 is an apocalyptic number.
It is an amenable number.
1411150302205 is a deficient number, since it is larger than the sum of its proper divisors (565317965315).
1411150302205 is an equidigital number, since it uses as much as digits as its factorization.
1411150302205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 857842188.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 1411150302205 its reverse (5022030511141), we get a palindrome (6433180813346).
The spelling of 1411150302205 in words is "one trillion, four hundred eleven billion, one hundred fifty million, three hundred two thousand, two hundred five".
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