Base | Representation |
---|---|
bin | 1100110101011001100000… |
… | …1110000111100110011111 |
3 | 1211222001022012010022220122 |
4 | 3031112120032013212133 |
5 | 3322200343434432333 |
6 | 50002424325505155 |
7 | 2654344440560105 |
oct | 315263016074637 |
9 | 54861265108818 |
10 | 14111521405343 |
11 | 4550731a4608a |
12 | 16baaa7b721bb |
13 | 7b49316c90ab |
14 | 36b003727c75 |
15 | 19711686c798 |
hex | cd59838799f |
14111521405343 has 2 divisors, whose sum is σ = 14111521405344. Its totient is φ = 14111521405342.
The previous prime is 14111521405307. The next prime is 14111521405357. The reversal of 14111521405343 is 34350412511141.
It is a strong prime.
It is an emirp because it is prime and its reverse (34350412511141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14111521405343 - 226 = 14111454296479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111521402343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055760702671 + 7055760702672.
It is an arithmetic number, because the mean of its divisors is an integer number (7055760702672).
Almost surely, 214111521405343 is an apocalyptic number.
14111521405343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111521405343 is an equidigital number, since it uses as much as digits as its factorization.
14111521405343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 14111521405343 its reverse (34350412511141), we get a palindrome (48461933916484).
The spelling of 14111521405343 in words is "fourteen trillion, one hundred eleven billion, five hundred twenty-one million, four hundred five thousand, three hundred forty-three".
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