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34350412511141 is a prime number
BaseRepresentation
bin1111100111101110101000…
…01000101011011110100101
311111121212102022100101200122
413303313110020223132211
514000244121100324031
6201020210041251325
710143510146531066
oct763672410533645
9144555368311618
1034350412511141
11aa43a23392771
123a2940b793b45
1316222cb40841c
1486a7d6c5c56d
153e87ee11d47b
hex1f3dd422b7a5

34350412511141 has 2 divisors, whose sum is σ = 34350412511142. Its totient is φ = 34350412511140.

The previous prime is 34350412511137. The next prime is 34350412511179. The reversal of 34350412511141 is 14111521405343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31439805908641 + 2910606602500 = 5607121^2 + 1706050^2 .

It is an emirp because it is prime and its reverse (14111521405343) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34350412511141 - 22 = 34350412511137 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34350412511111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17175206255570 + 17175206255571.

It is an arithmetic number, because the mean of its divisors is an integer number (17175206255571).

Almost surely, 234350412511141 is an apocalyptic number.

It is an amenable number.

34350412511141 is a deficient number, since it is larger than the sum of its proper divisors (1).

34350412511141 is an equidigital number, since it uses as much as digits as its factorization.

34350412511141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 34350412511141 its reverse (14111521405343), we get a palindrome (48461933916484).

The spelling of 34350412511141 in words is "thirty-four trillion, three hundred fifty billion, four hundred twelve million, five hundred eleven thousand, one hundred forty-one".