14111532551113 has 2 divisors, whose sum is σ = 14111532551114. Its totient is φ = 14111532551112.

The previous prime is 14111532551111. The next prime is 14111532551117. The reversal of 14111532551113 is 31115523511141.

14111532551113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13983949998144 + 127582552969 = 3739512^2 + 357187^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111532551113 - 2¹ = 14111532551111 is a prime.

It is a super-2 number, since 2×14111532551113² (a number of 27 digits) contains 22 as substring.

Together with 14111532551111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14111532551111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055766275556 + 7055766275557.

It is an arithmetic number, because the mean of its divisors is an integer number (7055766275557).

Almost surely, 2^{14111532551113} is an apocalyptic number.

It is an amenable number.

14111532551113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111532551113 is an equidigital number, since it uses as much as digits as its factorization.

14111532551113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9000, while the sum is 34.

The spelling of 14111532551113 in words is "fourteen trillion, one hundred eleven billion, five hundred thirty-two million, five hundred fifty-one thousand, one hundred thirteen".