Base | Representation |
---|---|
bin | 1100110101011011011010… |
… | …1011111101011010111000 |
3 | 1211222002121210220212221022 |
4 | 3031112312223331122320 |
5 | 3322202420312410230 |
6 | 50002551145202012 |
7 | 2654363215306415 |
oct | 315266653753270 |
9 | 54862553825838 |
10 | 14112032544440 |
11 | 4550974520496 |
12 | 16bb00b190308 |
13 | 7b49b358136c |
14 | 36b05157d10c |
15 | 1971466861e5 |
hex | cd5b6afd6b8 |
14112032544440 has 32 divisors (see below), whose sum is σ = 31767722532000. Its totient is φ = 5642030918784.
The previous prime is 14112032544391. The next prime is 14112032544481. The reversal of 14112032544440 is 4444523021141.
It is a self number, because there is not a number n which added to its sum of digits gives 14112032544440.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86858420 + ... + 87020739.
It is an arithmetic number, because the mean of its divisors is an integer number (992741329125).
Almost surely, 214112032544440 is an apocalyptic number.
14112032544440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14112032544440 is an abundant number, since it is smaller than the sum of its proper divisors (17655689987560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112032544440 is a wasteful number, since it uses less digits than its factorization.
14112032544440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173881199 (or 173881195 counting only the distinct ones).
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 14112032544440 its reverse (4444523021141), we get a palindrome (18556555565581).
The spelling of 14112032544440 in words is "fourteen trillion, one hundred twelve billion, thirty-two million, five hundred forty-four thousand, four hundred forty".
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