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14112034420013 is a prime number
BaseRepresentation
bin1100110101011011011011…
…0011000111010100101101
31211222002121221110011201222
43031112312303013110231
53322202421302420023
650002551253313125
72654363240250515
oct315266663072455
954862557404658
1014112034420013
114550975591652
1216bb00b9357a5
137b49b3a89c7a
1436b05190a845
15197146906cc8
hexcd5b6cc752d

14112034420013 has 2 divisors, whose sum is σ = 14112034420014. Its totient is φ = 14112034420012.

The previous prime is 14112034420009. The next prime is 14112034420021. The reversal of 14112034420013 is 31002443021141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13855048284169 + 256986135844 = 3722237^2 + 506938^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112034420013 - 22 = 14112034420009 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14112034420313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056017210006 + 7056017210007.

It is an arithmetic number, because the mean of its divisors is an integer number (7056017210007).

Almost surely, 214112034420013 is an apocalyptic number.

It is an amenable number.

14112034420013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112034420013 is an equidigital number, since it uses as much as digits as its factorization.

14112034420013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14112034420013 its reverse (31002443021141), we get a palindrome (45114477441154).

The spelling of 14112034420013 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred twenty thousand, thirteen".