Base | Representation |
---|---|
bin | 1100110101011011011011… |
… | …0011000111010100101101 |
3 | 1211222002121221110011201222 |
4 | 3031112312303013110231 |
5 | 3322202421302420023 |
6 | 50002551253313125 |
7 | 2654363240250515 |
oct | 315266663072455 |
9 | 54862557404658 |
10 | 14112034420013 |
11 | 4550975591652 |
12 | 16bb00b9357a5 |
13 | 7b49b3a89c7a |
14 | 36b05190a845 |
15 | 197146906cc8 |
hex | cd5b6cc752d |
14112034420013 has 2 divisors, whose sum is σ = 14112034420014. Its totient is φ = 14112034420012.
The previous prime is 14112034420009. The next prime is 14112034420021. The reversal of 14112034420013 is 31002443021141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13855048284169 + 256986135844 = 3722237^2 + 506938^2 .
It is a cyclic number.
It is not a de Polignac number, because 14112034420013 - 22 = 14112034420009 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14112034420313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056017210006 + 7056017210007.
It is an arithmetic number, because the mean of its divisors is an integer number (7056017210007).
Almost surely, 214112034420013 is an apocalyptic number.
It is an amenable number.
14112034420013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112034420013 is an equidigital number, since it uses as much as digits as its factorization.
14112034420013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 14112034420013 its reverse (31002443021141), we get a palindrome (45114477441154).
The spelling of 14112034420013 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred twenty thousand, thirteen".
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