Base | Representation |
---|---|
bin | 1100110101011011011011… |
… | …0011000111010100110101 |
3 | 1211222002121221110011202021 |
4 | 3031112312303013110311 |
5 | 3322202421302420041 |
6 | 50002551253313141 |
7 | 2654363240250526 |
oct | 315266663072465 |
9 | 54862557404667 |
10 | 14112034420021 |
11 | 455097559165a |
12 | 16bb00b9357b1 |
13 | 7b49b3a89c85 |
14 | 36b05190a84d |
15 | 197146906cd1 |
hex | cd5b6cc7535 |
14112034420021 has 2 divisors, whose sum is σ = 14112034420022. Its totient is φ = 14112034420020.
The previous prime is 14112034420013. The next prime is 14112034420061. The reversal of 14112034420021 is 12002443021141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10381535317521 + 3730499102500 = 3222039^2 + 1931450^2 .
It is a cyclic number.
It is not a de Polignac number, because 14112034420021 - 23 = 14112034420013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14112034420061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056017210010 + 7056017210011.
It is an arithmetic number, because the mean of its divisors is an integer number (7056017210011).
Almost surely, 214112034420021 is an apocalyptic number.
It is an amenable number.
14112034420021 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112034420021 is an equidigital number, since it uses as much as digits as its factorization.
14112034420021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14112034420021 its reverse (12002443021141), we get a palindrome (26114477441162).
The spelling of 14112034420021 in words is "fourteen trillion, one hundred twelve billion, thirty-four million, four hundred twenty thousand, twenty-one".
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