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1411212243013 is a prime number
BaseRepresentation
bin10100100010010010110…
…011011111000001000101
311222220120210210202101121
4110202102303133001011
5141110130313234023
63000145115553541
7203646104101126
oct24422263370105
94886523722347
101411212243013
114a4545580431
121a960415b8b1
13a30cc7b42b1
144c43576804d
1526a97675d5d
hex14892cdf045

1411212243013 has 2 divisors, whose sum is σ = 1411212243014. Its totient is φ = 1411212243012.

The previous prime is 1411212242983. The next prime is 1411212243047. The reversal of 1411212243013 is 3103422121141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 919147873284 + 492064369729 = 958722^2 + 701473^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411212243013 - 25 = 1411212242981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411212243083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705606121506 + 705606121507.

It is an arithmetic number, because the mean of its divisors is an integer number (705606121507).

Almost surely, 21411212243013 is an apocalyptic number.

It is an amenable number.

1411212243013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411212243013 is an equidigital number, since it uses as much as digits as its factorization.

1411212243013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1411212243013 its reverse (3103422121141), we get a palindrome (4514634364154).

The spelling of 1411212243013 in words is "one trillion, four hundred eleven billion, two hundred twelve million, two hundred forty-three thousand, thirteen".