Base | Representation |
---|---|
bin | 100000000101100110100000… |
… | …011000011110001010100010 |
3 | 200111200011122212121001112121 |
4 | 200011212200120132022202 |
5 | 121444122214342323432 |
6 | 1220050425551214454 |
7 | 41503521255140512 |
oct | 4005464030361242 |
9 | 614604585531477 |
10 | 141122431214242 |
11 | 40a69761403525 |
12 | 139b258081742a |
13 | 6098a3278aaba |
14 | 26bc50d903842 |
15 | 114adb9398197 |
hex | 8059a061e2a2 |
141122431214242 has 32 divisors (see below), whose sum is σ = 222126329147904. Its totient is φ = 67155939561600.
The previous prime is 141122431214231. The next prime is 141122431214293. The reversal of 141122431214242 is 242412134221141.
It is a junction number, because it is equal to n+sod(n) for n = 141122431214198 and 141122431214207.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23587918 + ... + 28959190.
It is an arithmetic number, because the mean of its divisors is an integer number (6941447785872).
Almost surely, 2141122431214242 is an apocalyptic number.
141122431214242 is a deficient number, since it is larger than the sum of its proper divisors (81003897933662).
141122431214242 is a wasteful number, since it uses less digits than its factorization.
141122431214242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5378314.
The product of its digits is 24576, while the sum is 34.
Adding to 141122431214242 its reverse (242412134221141), we get a palindrome (383534565435383).
The spelling of 141122431214242 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirty-one million, two hundred fourteen thousand, two hundred forty-two".
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