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141122431214310 = 2357131912516131759
BaseRepresentation
bin100000000101100110100000…
…011000011110001011100110
3200111200011122212121001122010
4200011212200120132023212
5121444122214342324220
61220050425551215050
741503521255140640
oct4005464030361346
9614604585531563
10141122431214310
1140a69761403587
12139b2580817486
136098a3278ab40
1426bc50d903890
15114adb93981e0
hex8059a061e2e6

141122431214310 has 512 divisors, whose sum is σ = 421631769968640. Its totient is φ = 29436514560000.

The previous prime is 141122431214293. The next prime is 141122431214393. The reversal of 141122431214310 is 13412134221141.

It is a super-2 number, since 2×1411224312143102 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 80228783211 + ... + 80228784969.

It is an arithmetic number, because the mean of its divisors is an integer number (823499550720).

Almost surely, 2141122431214310 is an apocalyptic number.

141122431214310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 141122431214310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (210815884984320).

141122431214310 is an abundant number, since it is smaller than the sum of its proper divisors (280509338754330).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141122431214310 is a wasteful number, since it uses less digits than its factorization.

141122431214310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2844.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 141122431214310 its reverse (13412134221141), we get a palindrome (154534565435451).

The spelling of 141122431214310 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirty-one million, two hundred fourteen thousand, three hundred ten".