141125154042317 has 2 divisors, whose sum is σ = 141125154042318. Its totient is φ = 141125154042316.

The previous prime is 141125154042199. The next prime is 141125154042319. The reversal of 141125154042317 is 713240451521141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130529048354761 + 10596105687556 = 11424931^2 + 3255166^2 .

It is a cyclic number.

It is not a de Polignac number, because 141125154042317 - 2¹² = 141125154038221 is a prime.

Together with 141125154042319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141125154042319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562577021158 + 70562577021159.

It is an arithmetic number, because the mean of its divisors is an integer number (70562577021159).

Almost surely, 2^{141125154042317} is an apocalyptic number.

It is an amenable number.

141125154042317 is a deficient number, since it is larger than the sum of its proper divisors (1).

141125154042317 is an equidigital number, since it uses as much as digits as its factorization.

141125154042317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 41.

The spelling of 141125154042317 in words is "one hundred forty-one trillion, one hundred twenty-five billion, one hundred fifty-four million, forty-two thousand, three hundred seventeen".