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141125694893 is a prime number
BaseRepresentation
bin1000001101101110111…
…1110011010110101101
3111111021021220002211122
42003123233303112231
54303011134214033
6144455433230325
713124140420421
oct2033357632655
9444237802748
10141125694893
115493a8593a7
12234268623a5
1310400b6b251
146b8ad38b81
153a0e980a98
hex20dbbf35ad

141125694893 has 2 divisors, whose sum is σ = 141125694894. Its totient is φ = 141125694892.

The previous prime is 141125694883. The next prime is 141125694943. The reversal of 141125694893 is 398496521141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 141125694889 + 4 = 375667^2 + 2^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141125694893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141125694833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562847446 + 70562847447.

It is an arithmetic number, because the mean of its divisors is an integer number (70562847447).

Almost surely, 2141125694893 is an apocalyptic number.

It is an amenable number.

141125694893 is a deficient number, since it is larger than the sum of its proper divisors (1).

141125694893 is an equidigital number, since it uses as much as digits as its factorization.

141125694893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1866240, while the sum is 53.

The spelling of 141125694893 in words is "one hundred forty-one billion, one hundred twenty-five million, six hundred ninety-four thousand, eight hundred ninety-three".