Base | Representation |
---|---|
bin | 1100110101011111001000… |
… | …1010111100000100011000 |
3 | 1211222012012100210100120021 |
4 | 3031113302022330010120 |
5 | 3322211441303133422 |
6 | 50003234155240224 |
7 | 2654430024052405 |
oct | 315276212740430 |
9 | 54865170710507 |
10 | 14113030521112 |
11 | 45513368920a6 |
12 | 16bb249449074 |
13 | 7b4b122605c3 |
14 | 36b107d212ac |
15 | 1971a40b7dc7 |
hex | cd5f22bc118 |
14113030521112 has 32 divisors (see below), whose sum is σ = 26644733146800. Its totient is φ = 7007871961600.
The previous prime is 14113030521053. The next prime is 14113030521113. The reversal of 14113030521112 is 21112503031141.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14113030521113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5385589 + ... + 7565092.
Almost surely, 214113030521112 is an apocalyptic number.
It is an amenable number.
14113030521112 is a deficient number, since it is larger than the sum of its proper divisors (12531702625688).
14113030521112 is a wasteful number, since it uses less digits than its factorization.
14113030521112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12951627 (or 12951623 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 14113030521112 its reverse (21112503031141), we get a palindrome (35225533552253).
The spelling of 14113030521112 in words is "fourteen trillion, one hundred thirteen billion, thirty million, five hundred twenty-one thousand, one hundred twelve".
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