Base | Representation |
---|---|
bin | 100000000101101110101101… |
… | …100011110000110000110010 |
3 | 200111201000101221001010202210 |
4 | 200011232231203300300302 |
5 | 121444243241001244102 |
6 | 1220054444141352550 |
7 | 41504252514322011 |
oct | 4005565543606062 |
9 | 614630357033683 |
10 | 141131242212402 |
11 | 40a72472a43892 |
12 | 139b421b568756 |
13 | 6099808034a90 |
14 | 26bcb07b9aa78 |
15 | 114b232b8e36c |
hex | 805bad8f0c32 |
141131242212402 has 64 divisors (see below), whose sum is σ = 304159778979840. Its totient is φ = 43398605957184.
The previous prime is 141131242212391. The next prime is 141131242212409. The reversal of 141131242212402 is 204212242131141.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 141131242212402.
It is not an unprimeable number, because it can be changed into a prime (141131242212409) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 914346549 + ... + 914500887.
It is an arithmetic number, because the mean of its divisors is an integer number (4752496546560).
Almost surely, 2141131242212402 is an apocalyptic number.
141131242212402 is an abundant number, since it is smaller than the sum of its proper divisors (163028536767438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141131242212402 is a wasteful number, since it uses less digits than its factorization.
141131242212402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161407.
The product of its (nonzero) digits is 6144, while the sum is 30.
Adding to 141131242212402 its reverse (204212242131141), we get a palindrome (345343484343543).
The spelling of 141131242212402 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred forty-two million, two hundred twelve thousand, four hundred two".
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