Base | Representation |
---|---|
bin | 10100100010011000110… |
… | …111110100010110111101 |
3 | 11222220211220100200202121 |
4 | 110202120313310112331 |
5 | 141110332343323201 |
6 | 3000203153522541 |
7 | 203651451266062 |
oct | 24423067642675 |
9 | 4886756320677 |
10 | 1411314042301 |
11 | 4a4597a90779 |
12 | 1a9632273451 |
13 | a3117907a67 |
14 | 4c4450a6c69 |
15 | 26aa15839a1 |
hex | 14898df45bd |
1411314042301 has 2 divisors, whose sum is σ = 1411314042302. Its totient is φ = 1411314042300.
The previous prime is 1411314042293. The next prime is 1411314042317. The reversal of 1411314042301 is 1032404131141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1161708886276 + 249605156025 = 1077826^2 + 499605^2 .
It is a cyclic number.
It is not a de Polignac number, because 1411314042301 - 23 = 1411314042293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1411317042301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705657021150 + 705657021151.
It is an arithmetic number, because the mean of its divisors is an integer number (705657021151).
Almost surely, 21411314042301 is an apocalyptic number.
It is an amenable number.
1411314042301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411314042301 is an equidigital number, since it uses as much as digits as its factorization.
1411314042301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1411314042301 its reverse (1032404131141), we get a palindrome (2443718173442).
The spelling of 1411314042301 in words is "one trillion, four hundred eleven billion, three hundred fourteen million, forty-two thousand, three hundred one".
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