Base | Representation |
---|---|
bin | 100000000101101111100010… |
… | …001000110010001111001000 |
3 | 200111201002200101220111202001 |
4 | 200011233202020302033020 |
5 | 121444302042312124000 |
6 | 1220055111452320344 |
7 | 41504313415243123 |
oct | 4005574210621710 |
9 | 614632611814661 |
10 | 141132124333000 |
11 | 40a72885974079 |
12 | 139b4426a730b4 |
13 | 6099918a0b328 |
14 | 26bcb8cdc13ba |
15 | 114b28533846a |
hex | 805be22323c8 |
141132124333000 has 128 divisors (see below), whose sum is σ = 341670999852000. Its totient is φ = 54500786995200.
The previous prime is 141132124332989. The next prime is 141132124333019. The reversal of 141132124333000 is 333421231141.
It can be written as a sum of positive squares in 16 ways, for example, as 18437113471716 + 122695010861284 = 4293846^2 + 11076778^2 .
It is a super-3 number, since 3×1411321243330003 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 141132124333000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 298144504 + ... + 298617496.
Almost surely, 2141132124333000 is an apocalyptic number.
141132124333000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141132124333000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170835499926000).
141132124333000 is an abundant number, since it is smaller than the sum of its proper divisors (200538875519000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141132124333000 is a wasteful number, since it uses less digits than its factorization.
141132124333000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 483332 (or 483318 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 141132124333000 its reverse (333421231141), we get a palindrome (141465545564141).
The spelling of 141132124333000 in words is "one hundred forty-one trillion, one hundred thirty-two billion, one hundred twenty-four million, three hundred thirty-three thousand".
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