Base | Representation |
---|---|
bin | 10100100010011001010… |
… | …111011001100001111111 |
3 | 11222220212110221022000221 |
4 | 110202121113121201333 |
5 | 141110342003233043 |
6 | 3000204051202211 |
7 | 203651611536226 |
oct | 24423127314177 |
9 | 4886773838027 |
10 | 1411322321023 |
11 | 4a45a172569a |
12 | 1a9634ba6367 |
13 | a3119546004 |
14 | 4c44621dcbd |
15 | 26aa216b8ed |
hex | 148995d987f |
1411322321023 has 2 divisors, whose sum is σ = 1411322321024. Its totient is φ = 1411322321022.
The previous prime is 1411322320979. The next prime is 1411322321029. The reversal of 1411322321023 is 3201232231141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1411322321023 - 221 = 1411320223871 is a prime.
It is a super-3 number, since 3×14113223210233 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1411322321029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705661160511 + 705661160512.
It is an arithmetic number, because the mean of its divisors is an integer number (705661160512).
Almost surely, 21411322321023 is an apocalyptic number.
1411322321023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411322321023 is an equidigital number, since it uses as much as digits as its factorization.
1411322321023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1411322321023 its reverse (3201232231141), we get a palindrome (4612554552164).
The spelling of 1411322321023 in words is "one trillion, four hundred eleven billion, three hundred twenty-two million, three hundred twenty-one thousand, twenty-three".
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