141132300400411 has 2 divisors, whose sum is σ = 141132300400412. Its totient is φ = 141132300400410.

The previous prime is 141132300400309. The next prime is 141132300400453. The reversal of 141132300400411 is 114004003231141.

141132300400411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141132300400411 - 2²¹ = 141132298303259 is a prime.

It is a super-3 number, since 3×141132300400411³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (141132300400471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70566150200205 + 70566150200206.

It is an arithmetic number, because the mean of its divisors is an integer number (70566150200206).

Almost surely, 2^{141132300400411} is an apocalyptic number.

141132300400411 is a deficient number, since it is larger than the sum of its proper divisors (1).

141132300400411 is an equidigital number, since it uses as much as digits as its factorization.

141132300400411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141132300400411 its reverse (114004003231141), we get a palindrome (255136303631552).

The spelling of 141132300400411 in words is "one hundred forty-one trillion, one hundred thirty-two billion, three hundred million, four hundred thousand, four hundred eleven".