141132300400410 has 128 divisors (see below), whose sum is σ = 382341736200960. Its totient is φ = 33026324889600.

The previous prime is 141132300400309. The next prime is 141132300400411. The reversal of 141132300400410 is 14004003231141.

It is a super-3 number, since 3×141132300400410³ (a number of 43 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141132300400411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 38967450 + ... + 42434970.

It is an arithmetic number, because the mean of its divisors is an integer number (2987044814070).

Almost surely, 2^{141132300400410} is an apocalyptic number.

141132300400410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 141132300400410, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191170868100480).

141132300400410 is an abundant number, since it is smaller than the sum of its proper divisors (241209435800550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132300400410 is a wasteful number, since it uses less digits than its factorization.

141132300400410 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3471824.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 141132300400410 its reverse (14004003231141), we get a palindrome (155136303631551).

The spelling of 141132300400410 in words is "one hundred forty-one trillion, one hundred thirty-two billion, three hundred million, four hundred thousand, four hundred ten".