141132342123140 has 24 divisors (see below), whose sum is σ = 296508654292032. Its totient is φ = 56428034785760.

The previous prime is 141132342123137. The next prime is 141132342123217. The reversal of 141132342123140 is 41321243231141.

It is a super-3 number, since 3×141132342123140³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141132342123097 and 141132342123106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1556332496 + ... + 1556423175.

It is an arithmetic number, because the mean of its divisors is an integer number (12354527262168).

Almost surely, 2^{141132342123140} is an apocalyptic number.

141132342123140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141132342123140 is an abundant number, since it is smaller than the sum of its proper divisors (155376312168892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132342123140 is a wasteful number, since it uses less digits than its factorization.

141132342123140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3112757947 (or 3112757945 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 141132342123140 its reverse (41321243231141), we get a palindrome (182453585354281).

The spelling of 141132342123140 in words is "one hundred forty-one trillion, one hundred thirty-two billion, three hundred forty-two million, one hundred twenty-three thousand, one hundred forty".