Base | Representation |
---|---|
bin | 100000000101101111111001… |
… | …110110101100110011101111 |
3 | 200111201010201010122112212211 |
4 | 200011233321312230303233 |
5 | 121444303401143322414 |
6 | 1220055215145111251 |
7 | 41504326316401351 |
oct | 4005577166546357 |
9 | 614633633575784 |
10 | 141132522245359 |
11 | 40a72a6a543567 |
12 | 139b4518188527 |
13 | 609998029b628 |
14 | 26bcbc9ba10d1 |
15 | 114b2aa2383c4 |
hex | 805bf9daccef |
141132522245359 has 2 divisors, whose sum is σ = 141132522245360. Its totient is φ = 141132522245358.
The previous prime is 141132522245293. The next prime is 141132522245383. The reversal of 141132522245359 is 953542225231141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141132522245359 - 213 = 141132522237167 is a prime.
It is a super-3 number, since 3×1411325222453593 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141132522249359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70566261122679 + 70566261122680.
It is an arithmetic number, because the mean of its divisors is an integer number (70566261122680).
Almost surely, 2141132522245359 is an apocalyptic number.
141132522245359 is a deficient number, since it is larger than the sum of its proper divisors (1).
141132522245359 is an equidigital number, since it uses as much as digits as its factorization.
141132522245359 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592000, while the sum is 49.
The spelling of 141132522245359 in words is "one hundred forty-one trillion, one hundred thirty-two billion, five hundred twenty-two million, two hundred forty-five thousand, three hundred fifty-nine".
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