141132522237167 has 2 divisors, whose sum is σ = 141132522237168. Its totient is φ = 141132522237166.

The previous prime is 141132522237139. The next prime is 141132522237169. The reversal of 141132522237167 is 761732225231141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141132522237167 - 2⁶ = 141132522237103 is a prime.

It is a super-3 number, since 3×141132522237167³ (a number of 43 digits) contains 333 as substring.

Together with 141132522237169, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141132522237169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70566261118583 + 70566261118584.

It is an arithmetic number, because the mean of its divisors is an integer number (70566261118584).

Almost surely, 2^{141132522237167} is an apocalyptic number.

141132522237167 is a deficient number, since it is larger than the sum of its proper divisors (1).

141132522237167 is an equidigital number, since it uses as much as digits as its factorization.

141132522237167 is an evil number, because the sum of its binary digits is even.

The product of its digits is 846720, while the sum is 47.

The spelling of 141132522237167 in words is "one hundred forty-one trillion, one hundred thirty-two billion, five hundred twenty-two million, two hundred thirty-seven thousand, one hundred sixty-seven".