Base | Representation |
---|---|
bin | 11010010010011101… |
… | …00000100011110000 |
3 | 1100102120221010210021 |
4 | 31021032200203300 |
5 | 212401020121112 |
6 | 10252244013224 |
7 | 1006513164214 |
oct | 151116404360 |
9 | 40376833707 |
10 | 14113442032 |
11 | 5a92740988 |
12 | 289a691214 |
13 | 143bc7ab41 |
14 | 97c5a6944 |
15 | 579090907 |
hex | 3493a08f0 |
14113442032 has 10 divisors (see below), whose sum is σ = 27344793968. Its totient is φ = 7056721008.
The previous prime is 14113442011. The next prime is 14113442051. The reversal of 14113442032 is 23024431141.
It is a junction number, because it is equal to n+sod(n) for n = 14113441988 and 14113442006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 441045048 + ... + 441045079.
Almost surely, 214113442032 is an apocalyptic number.
It is an amenable number.
14113442032 is a deficient number, since it is larger than the sum of its proper divisors (13231351936).
14113442032 is an equidigital number, since it uses as much as digits as its factorization.
14113442032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 882090135 (or 882090129 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14113442032 its reverse (23024431141), we get a palindrome (37137873173).
It can be divided in two parts, 1411 and 3442032, that added together give a palindrome (3443443).
The spelling of 14113442032 in words is "fourteen billion, one hundred thirteen million, four hundred forty-two thousand, thirty-two".
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