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14114041121419 is a prime number
BaseRepresentation
bin1100110101100010111001…
…1010000100101010001011
31211222021210210102011120021
43031120232122010222023
53322221024011341134
650003522340041311
72654464045033111
oct315305632045213
954867723364507
1014114041121419
114551805296068
1216bb48b993237
137b4c4373c655
1436b1a222bab1
15197212b900b4
hexcd62e684a8b

14114041121419 has 2 divisors, whose sum is σ = 14114041121420. Its totient is φ = 14114041121418.

The previous prime is 14114041121417. The next prime is 14114041121443. The reversal of 14114041121419 is 91412114041141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14114041121419 - 21 = 14114041121417 is a prime.

It is a super-2 number, since 2×141140411214192 (a number of 27 digits) contains 22 as substring.

Together with 14114041121417, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14114041121417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057020560709 + 7057020560710.

It is an arithmetic number, because the mean of its divisors is an integer number (7057020560710).

Almost surely, 214114041121419 is an apocalyptic number.

14114041121419 is a deficient number, since it is larger than the sum of its proper divisors (1).

14114041121419 is an equidigital number, since it uses as much as digits as its factorization.

14114041121419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 34.

The spelling of 14114041121419 in words is "fourteen trillion, one hundred fourteen billion, forty-one million, one hundred twenty-one thousand, four hundred nineteen".