Base | Representation |
---|---|
bin | 100000000101110111111011… |
… | …100010011110000111110111 |
3 | 200111201221221202021202112121 |
4 | 200011313323202132013313 |
5 | 121444424023422300401 |
6 | 1220103202250500411 |
7 | 41505053014643134 |
oct | 4005677342360767 |
9 | 614657852252477 |
10 | 141141140431351 |
11 | 40a76692260225 |
12 | 139b6122434707 |
13 | 609a724906b78 |
14 | 26bd3a65c758b |
15 | 114b611b44ca1 |
hex | 805dfb89e1f7 |
141141140431351 has 2 divisors, whose sum is σ = 141141140431352. Its totient is φ = 141141140431350.
The previous prime is 141141140431337. The next prime is 141141140431397. The reversal of 141141140431351 is 153134041141141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141141140431351 - 219 = 141141139907063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141141140434351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570570215675 + 70570570215676.
It is an arithmetic number, because the mean of its divisors is an integer number (70570570215676).
Almost surely, 2141141140431351 is an apocalyptic number.
141141140431351 is a deficient number, since it is larger than the sum of its proper divisors (1).
141141140431351 is an equidigital number, since it uses as much as digits as its factorization.
141141140431351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 34.
Adding to 141141140431351 its reverse (153134041141141), we get a palindrome (294275181572492).
The spelling of 141141140431351 in words is "one hundred forty-one trillion, one hundred forty-one billion, one hundred forty million, four hundred thirty-one thousand, three hundred fifty-one".
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