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141141141030343 is a prime number
BaseRepresentation
bin100000000101110111111011…
…100100110000010111000111
3200111201221221210102012012111
4200011313323210300113013
5121444424024100432333
61220103202311401451
741505053023016356
oct4005677344602707
9614657853365174
10141141141030343
1140a7669262a263
12139b6122683287
13609a724a866bc
1426bd3a670199d
15114b611c124cd
hex805dfb9305c7

141141141030343 has 2 divisors, whose sum is σ = 141141141030344. Its totient is φ = 141141141030342.

The previous prime is 141141141030259. The next prime is 141141141030389. The reversal of 141141141030343 is 343030141141141.

It is a happy number.

141141141030343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141141141030343 - 221 = 141141138933191 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141141141030143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570570515171 + 70570570515172.

It is an arithmetic number, because the mean of its divisors is an integer number (70570570515172).

Almost surely, 2141141141030343 is an apocalyptic number.

141141141030343 is a deficient number, since it is larger than the sum of its proper divisors (1).

141141141030343 is an equidigital number, since it uses as much as digits as its factorization.

141141141030343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141141141030343 its reverse (343030141141141), we get a palindrome (484171282171484).

The spelling of 141141141030343 in words is "one hundred forty-one trillion, one hundred forty-one billion, one hundred forty-one million, thirty thousand, three hundred forty-three".