Base | Representation |
---|---|
bin | 100000000101110111111011… |
… | …100100110000010111000111 |
3 | 200111201221221210102012012111 |
4 | 200011313323210300113013 |
5 | 121444424024100432333 |
6 | 1220103202311401451 |
7 | 41505053023016356 |
oct | 4005677344602707 |
9 | 614657853365174 |
10 | 141141141030343 |
11 | 40a7669262a263 |
12 | 139b6122683287 |
13 | 609a724a866bc |
14 | 26bd3a670199d |
15 | 114b611c124cd |
hex | 805dfb9305c7 |
141141141030343 has 2 divisors, whose sum is σ = 141141141030344. Its totient is φ = 141141141030342.
The previous prime is 141141141030259. The next prime is 141141141030389. The reversal of 141141141030343 is 343030141141141.
It is a happy number.
141141141030343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141141141030343 - 221 = 141141138933191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141141141030143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570570515171 + 70570570515172.
It is an arithmetic number, because the mean of its divisors is an integer number (70570570515172).
Almost surely, 2141141141030343 is an apocalyptic number.
141141141030343 is a deficient number, since it is larger than the sum of its proper divisors (1).
141141141030343 is an equidigital number, since it uses as much as digits as its factorization.
141141141030343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 141141141030343 its reverse (343030141141141), we get a palindrome (484171282171484).
The spelling of 141141141030343 in words is "one hundred forty-one trillion, one hundred forty-one billion, one hundred forty-one million, thirty thousand, three hundred forty-three".
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