Base | Representation |
---|---|
bin | 1100110101100011100010… |
… | …1010010010001101110010 |
3 | 1211222022020210002210101010 |
4 | 3031120320222102031302 |
5 | 3322221402031042120 |
6 | 50003551403051350 |
7 | 2654501234143002 |
oct | 315307052221562 |
9 | 54868223083333 |
10 | 14114213143410 |
11 | 45518933a97a6 |
12 | 16bb519510b56 |
13 | 7b4c7027c103 |
14 | 36b1bb00a002 |
15 | 197222d1e7e0 |
hex | cd638a92372 |
14114213143410 has 32 divisors (see below), whose sum is σ = 33886570037760. Its totient is φ = 3762405894528.
The previous prime is 14114213143307. The next prime is 14114213143447. The reversal of 14114213143410 is 1434131241141.
It is a super-2 number, since 2×141142131434102 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86434387 + ... + 86597526.
It is an arithmetic number, because the mean of its divisors is an integer number (1058955313680).
Almost surely, 214114213143410 is an apocalyptic number.
14114213143410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14114213143410 is an abundant number, since it is smaller than the sum of its proper divisors (19772356894350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14114213143410 is a wasteful number, since it uses less digits than its factorization.
14114213143410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173034642.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 14114213143410 its reverse (1434131241141), we get a palindrome (15548344384551).
The spelling of 14114213143410 in words is "fourteen trillion, one hundred fourteen billion, two hundred thirteen million, one hundred forty-three thousand, four hundred ten".
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