Base | Representation |
---|---|
bin | 1100110101100110011110… |
… | …0101110100001111100111 |
3 | 1211222101021122122201020121 |
4 | 3031121213211310033213 |
5 | 3322230010112014343 |
6 | 50004201450542411 |
7 | 2654526604443556 |
oct | 315314745641747 |
9 | 54871248581217 |
10 | 14115000501223 |
11 | 4552157895336 |
12 | 16bb6b9137a07 |
13 | 7b50674268cb |
14 | 36b253803d9d |
15 | 19726beeaaed |
hex | cd6679743e7 |
14115000501223 has 2 divisors, whose sum is σ = 14115000501224. Its totient is φ = 14115000501222.
The previous prime is 14115000501211. The next prime is 14115000501271. The reversal of 14115000501223 is 32210500051141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14115000501223 - 241 = 11915977245671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14115000501523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057500250611 + 7057500250612.
It is an arithmetic number, because the mean of its divisors is an integer number (7057500250612).
Almost surely, 214115000501223 is an apocalyptic number.
14115000501223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14115000501223 is an equidigital number, since it uses as much as digits as its factorization.
14115000501223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 14115000501223 its reverse (32210500051141), we get a palindrome (46325500552364).
The spelling of 14115000501223 in words is "fourteen trillion, one hundred fifteen billion, five hundred one thousand, two hundred twenty-three".
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