Base | Representation |
---|---|
bin | 10100100011000010100… |
… | …010001000101001100111 |
3 | 11222222122121120111021122 |
4 | 110203002202020221213 |
5 | 141113300312020234 |
6 | 3000400403004155 |
7 | 204004666323344 |
oct | 24430242105147 |
9 | 4888577514248 |
10 | 1412013001319 |
11 | 4a4916589a58 |
12 | 1a97a836965b |
13 | a31c967138b |
14 | 4c4adc4d7cb |
15 | 26ae2aec92e |
hex | 148c2888a67 |
1412013001319 has 2 divisors, whose sum is σ = 1412013001320. Its totient is φ = 1412013001318.
The previous prime is 1412013001279. The next prime is 1412013001327. The reversal of 1412013001319 is 9131003102141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1412013001319 - 212 = 1412012997223 is a prime.
It is a super-2 number, since 2×14120130013192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412010001319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706006500659 + 706006500660.
It is an arithmetic number, because the mean of its divisors is an integer number (706006500660).
Almost surely, 21412013001319 is an apocalyptic number.
1412013001319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412013001319 is an equidigital number, since it uses as much as digits as its factorization.
1412013001319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 1412013001319 in words is "one trillion, four hundred twelve billion, thirteen million, one thousand, three hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •