Base | Representation |
---|---|
bin | 1100110101111001100101… |
… | …0101110001010110011111 |
3 | 1211222212112010221111200112 |
4 | 3031132121111301112133 |
5 | 3322321011302420132 |
6 | 50010410452320235 |
7 | 2655100662505565 |
oct | 315363125612637 |
9 | 54885463844615 |
10 | 14120130123167 |
11 | 455434a386212 |
12 | 17006ab01307b |
13 | 7b56a409ab73 |
14 | 36b5bcba7a35 |
15 | 19746c508ab2 |
hex | cd79957159f |
14120130123167 has 2 divisors, whose sum is σ = 14120130123168. Its totient is φ = 14120130123166.
The previous prime is 14120130123163. The next prime is 14120130123179. The reversal of 14120130123167 is 76132103102141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14120130123167 - 22 = 14120130123163 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14120130123163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060065061583 + 7060065061584.
It is an arithmetic number, because the mean of its divisors is an integer number (7060065061584).
Almost surely, 214120130123167 is an apocalyptic number.
14120130123167 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120130123167 is an equidigital number, since it uses as much as digits as its factorization.
14120130123167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 14120130123167 in words is "fourteen trillion, one hundred twenty billion, one hundred thirty million, one hundred twenty-three thousand, one hundred sixty-seven".
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