Base | Representation |
---|---|
bin | 100000000110101111111101… |
… | …011111111000110110010111 |
3 | 200111221201020120111100010011 |
4 | 200012233331133320312113 |
5 | 122001420232012212332 |
6 | 1220150552200141051 |
7 | 41512312626035332 |
oct | 4006577537706627 |
9 | 614851216440104 |
10 | 141201302850967 |
11 | 40a9a155392577 |
12 | 13a05912767787 |
13 | 60a32c1bc0c28 |
14 | 26c2272879619 |
15 | 114ce8377be47 |
hex | 806bfd7f8d97 |
141201302850967 has 2 divisors, whose sum is σ = 141201302850968. Its totient is φ = 141201302850966.
The previous prime is 141201302850931. The next prime is 141201302850983. The reversal of 141201302850967 is 769058203102141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141201302850967 is a prime.
It is a super-3 number, since 3×1412013028509673 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 141201302850967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141201302850997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600651425483 + 70600651425484.
It is an arithmetic number, because the mean of its divisors is an integer number (70600651425484).
It is a 2-persistent number, because it is pandigital, and so is 2⋅141201302850967 = 282402605701934, but 3⋅141201302850967 = 423603908552901 is not.
Almost surely, 2141201302850967 is an apocalyptic number.
141201302850967 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201302850967 is an equidigital number, since it uses as much as digits as its factorization.
141201302850967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 49.
The spelling of 141201302850967 in words is "one hundred forty-one trillion, two hundred one billion, three hundred two million, eight hundred fifty thousand, nine hundred sixty-seven".
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