Search a number
-
+
141201303113112 = 2331171173275315817
BaseRepresentation
bin100000000110101111111101…
…100000111000110110011000
3200111221201020120222122201020
4200012233331200320312120
5122001420232044104422
61220150552205522440
741512312631206524
oct4006577540706630
9614851216878636
10141201303113112
1140a9a155551520
1213a05912873420
1360a32c1c83348
1426c2272906d84
15114ce837ce95c
hex806bfd838d98

141201303113112 has 256 divisors, whose sum is σ = 392943173483520. Its totient is φ = 41923888742400.

The previous prime is 141201303113089. The next prime is 141201303113137. The reversal of 141201303113112 is 211311303102141.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8927178228 + ... + 8927194044.

It is an arithmetic number, because the mean of its divisors is an integer number (1534934271420).

Almost surely, 2141201303113112 is an apocalyptic number.

141201303113112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141201303113112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196471586741760).

141201303113112 is an abundant number, since it is smaller than the sum of its proper divisors (251741870370408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141201303113112 is a wasteful number, since it uses less digits than its factorization.

141201303113112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18834 (or 18830 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 141201303113112 its reverse (211311303102141), we get a palindrome (352512606215253).

The spelling of 141201303113112 in words is "one hundred forty-one trillion, two hundred one billion, three hundred three million, one hundred thirteen thousand, one hundred twelve".