Base | Representation |
---|---|
bin | 100000000110110000000101… |
… | …111010110010101011111111 |
3 | 200111221201121102022121122022 |
4 | 200012300011322302223333 |
5 | 122001421024143340333 |
6 | 1220151014204110355 |
7 | 41512316262566324 |
oct | 4006600572625377 |
9 | 614851542277568 |
10 | 141201444121343 |
11 | 40a9a218102051 |
12 | 13a05951b353bb |
13 | 60a3315254578 |
14 | 26c2287530b4b |
15 | 114ce90d84c98 |
hex | 806c05eb2aff |
141201444121343 has 2 divisors, whose sum is σ = 141201444121344. Its totient is φ = 141201444121342.
The previous prime is 141201444121333. The next prime is 141201444121417. The reversal of 141201444121343 is 343121444102141.
141201444121343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141201444121343 - 24 = 141201444121327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141201444121333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600722060671 + 70600722060672.
It is an arithmetic number, because the mean of its divisors is an integer number (70600722060672).
Almost surely, 2141201444121343 is an apocalyptic number.
141201444121343 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201444121343 is an equidigital number, since it uses as much as digits as its factorization.
141201444121343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 141201444121343 its reverse (343121444102141), we get a palindrome (484322888223484).
The spelling of 141201444121343 in words is "one hundred forty-one trillion, two hundred one billion, four hundred forty-four million, one hundred twenty-one thousand, three hundred forty-three".
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