Base | Representation |
---|---|
bin | 100000000110110000000101… |
… | …111010110010101011110101 |
3 | 200111221201121102022121121221 |
4 | 200012300011322302223311 |
5 | 122001421024143340313 |
6 | 1220151014204110341 |
7 | 41512316262566311 |
oct | 4006600572625365 |
9 | 614851542277557 |
10 | 141201444121333 |
11 | 40a9a218102042 |
12 | 13a05951b353b1 |
13 | 60a331525456b |
14 | 26c2287530b41 |
15 | 114ce90d84c8d |
hex | 806c05eb2af5 |
141201444121333 has 2 divisors, whose sum is σ = 141201444121334. Its totient is φ = 141201444121332.
The previous prime is 141201444121327. The next prime is 141201444121343. The reversal of 141201444121333 is 333121444102141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124530824598244 + 16670619523089 = 11159338^2 + 4082967^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141201444121333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141201444121343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600722060666 + 70600722060667.
It is an arithmetic number, because the mean of its divisors is an integer number (70600722060667).
Almost surely, 2141201444121333 is an apocalyptic number.
It is an amenable number.
141201444121333 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201444121333 is an equidigital number, since it uses as much as digits as its factorization.
141201444121333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 141201444121333 its reverse (333121444102141), we get a palindrome (474322888223474).
The spelling of 141201444121333 in words is "one hundred forty-one trillion, two hundred one billion, four hundred forty-four million, one hundred twenty-one thousand, three hundred thirty-three".
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