Base | Representation |
---|---|
bin | 100000000110111001010001… |
… | …110010000111000100111010 |
3 | 200111222200001202210001220220 |
4 | 200012321101302013010322 |
5 | 122002101224023123240 |
6 | 1220155325004400510 |
7 | 41513115552440160 |
oct | 4006712162070472 |
9 | 614880052701826 |
10 | 141211306848570 |
11 | 40aa3419387a92 |
12 | 13a07844b46136 |
13 | 60a422767ab3a |
14 | 26c294135d230 |
15 | 114d36bb795d0 |
hex | 806e51c8713a |
141211306848570 has 32 divisors (see below), whose sum is σ = 387322441642368. Its totient is φ = 32276870136768.
The previous prime is 141211306848569. The next prime is 141211306848589. The reversal of 141211306848570 is 75848603112141.
It is a super-2 number, since 2×1412113068485702 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 336217397049 + ... + 336217397468.
It is an arithmetic number, because the mean of its divisors is an integer number (12103826301324).
Almost surely, 2141211306848570 is an apocalyptic number.
141211306848570 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
141211306848570 is an abundant number, since it is smaller than the sum of its proper divisors (246111134793798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141211306848570 is a wasteful number, since it uses less digits than its factorization.
141211306848570 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 672434794534.
The product of its (nonzero) digits is 1290240, while the sum is 51.
The spelling of 141211306848570 in words is "one hundred forty-one trillion, two hundred eleven billion, three hundred six million, eight hundred forty-eight thousand, five hundred seventy".
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