14121402311 has 2 divisors, whose sum is σ = 14121402312. Its totient is φ = 14121402310.

The previous prime is 14121402289. The next prime is 14121402313. The reversal of 14121402311 is 11320412141.

It is a strong prime.

It is an emirp because it is prime and its reverse (11320412141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14121402311 is a prime.

It is a super-2 number, since 2×14121402311² (a number of 21 digits) contains 22 as substring.

Together with 14121402313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14121402313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060701155 + 7060701156.

It is an arithmetic number, because the mean of its divisors is an integer number (7060701156).

Almost surely, 2^14121402311 is an apocalyptic number.

14121402311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121402311 is an equidigital number, since it uses as much as digits as its factorization.

14121402311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14121402311 its reverse (11320412141), we get a palindrome (25441814452).

The spelling of 14121402311 in words is "fourteen billion, one hundred twenty-one million, four hundred two thousand, three hundred eleven".